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Worked solution

Transform both variables without changing correlation

After a school physical fitness test, ten pupils have the following masses mm (kg) and overall scores ss.

Pupilmmss
A38.660
B41.858
C38.672
D54.159
E44.962
F32.194
G38.486
H41.462
I30.281
J52.454

(i) Calculate the product moment correlation coefficient between mm and ss for this sample.

(ii) Given u=10(m−30)u=10(m-30) and v=s−50v=s-50, calculate the product moment correlation coefficient between uu and vv for this sample.

CJC · Lecture · Example 9

(i) Correlate mass and score

Answer

rms=−0.762r_{ms}=-0.762 (3 s.f.).

Enter masses in L1 and scores in L2. Use STAT → CALC → 8:LinReg(a+bx) with Xlist=L1, Ylist=L2, then Calculate. The source screen gives a=124.9018952a=124.9018952, b=−1.360045944b=-1.360045944, r2=0.5807290052r^2=0.5807290052, r=−0.7620557756r=-0.7620557756. The requested result is the printed −0.762-0.762 to 3 s.f.

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(ii) Generate and pair the transformed lists

Answer

ruv=−0.762r_{uv}=-0.762 (3 s.f.).

Highlight the L3 heading, press ENTER, enter L3=10(L1−30), then ENTER. Highlight L4, press ENTER, enter L4=L2−50, then ENTER. The source screenshots retain all transformed values:

Pupiluuvv
A8610
B1188
C8622
D2419
E14912
F2144
G8436
H11412
I231
J2244

Use 8:LinReg(a+bx) with Xlist=L3, Ylist=L4. Calculator x now means uu, and calculator y means vv. The printed output is a=34.10051687a=34.10051687, b=−0.1360045944b=-0.1360045944, r2=0.5807290052r^2=0.5807290052, r=−0.7620557756r=-0.7620557756. Both scale factors are positive, so translation and rescaling leave rr unchanged. This is not a general rule for a single negative scale factor.

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Solution notes

Both complete original/transformed tables, calculator workflows and numerical screen outputs retained. The source’s general transformation statement is qualified in the lesson: a single negative scaling reverses the sign, and a zero scaling makes correlation undefined. No printed marks.