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Worked solution

Evaluate a derivative at a point with the source calculator workflow

Evaluate the first derivative of (a) y=x2y=x^2 when x=2x=2, and (b) y=ln⁡(2x3)y=\ln(2x^3) when x=5x=5.

CJC · Lecture · Example 14

(a) Open the numerical derivative template

The source’s self-reading calculator procedure gives two routes: press MATH, then 8:nDeriv(; or press ALPHA, then WINDOW, then 3:nDeriv(. Its first screen shows a derivative template with slots for the variable, function and evaluation point. These are the retained source calculator instructions, not a claim about every calculator model.

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(a) Enter the function and evaluation point

Fill the template with differentiation variable XX, function X2X^2 and evaluation point X=2X=2, then press ENTER. The second printed screen displays d(X2)/dX∣X=2\left.d(X^2)/dX\right|_{X=2} and result 4. Thus the first derivative at x=2x=2 is 4. Independently, y′=2xy^{\prime}=2x confirms the value.

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(b) Evaluate and preserve the stated precision

Use the numerical derivative template for ln⁡(2X3)\ln(2X^3) with respect to XX at X=5X=5. The printed result is 0.600 (to 3 s.f.). Independently, y′=6x2/(2x3)=3/xy^{\prime}=6x^2/(2x^3)=3/x on the real logarithm domain x>0x>0, so the exact value is 3/53/5. The source prints no separate screen or button sequence for this part.

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Common mistakes

A numerical derivative at one point is a value, not a symbolic derivative function. Preserve 0.600 when reporting three significant figures.

Solution notes

Both copies contain the same self-reading procedure, two calculator screenshots and printed results. Template slots, entered expression, evaluation point and result were read from the full-page renders; original embedded screenshots remain unchanged in the source-image archives. Symbolic confirmations are independently authored. No printed marks or past-paper attribution.

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