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Worked solution

Match derivatives in trigonometric composites

Integrate with respect to xx: (a) sin⁡(2−3x)\sin(2-3x); (b) sec⁡(3x)tan⁡(3x)\sec(3x)\tan(3x); (c) xcos⁡(3x2)x\cos(3x^2).

CJC · Lecture · Example 11

(a)

The Teacher scaffold is f=2−3xf=2-3x, f′=−3f^{\prime}=-3. Thus ∫sin⁡(2−3x) dx=−13∫(−3)sin⁡(2−3x) dx=13cos⁡(2−3x)+C\int\sin(2-3x)\,dx=-\frac13\int(-3)\sin(2-3x)\,dx=\frac13\cos(2-3x)+C.

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(b)

With f=3xf=3x, f′=3f^{\prime}=3, ∫sec⁡(3x)tan⁡(3x) dx=13∫3sec⁡(3x)tan⁡(3x) dx=13sec⁡(3x)+C\int\sec(3x)\tan(3x)\,dx=\frac13\int3\sec(3x)\tan(3x)\,dx=\frac13\sec(3x)+C, on intervals where cos⁡(3x)≠0\cos(3x)\ne0.

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(c)

With f=3x2f=3x^2, f′=6xf^{\prime}=6x, ∫xcos⁡(3x2) dx=16∫6xcos⁡(3x2) dx=16sin⁡(3x2)+C\int x\cos(3x^2)\,dx=\frac16\int6x\cos(3x^2)\,dx=\frac16\sin(3x^2)+C.

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Common mistakes

The negative inner derivative in (a) cancels the negative sign from integrating sine.

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