Worked solution
Find cutoffs from left-tail and right-tail areas
If , find
(i) such that and
(ii) such that .
CJC · Lecture · Example 2
(i) Left area 0.8907
The standard deviation is 6, not 36. The area left of a exceeds one half, so expect .
- Press 2 nd VARS, select 3:invNorm, then ENTER.
- In the source’s guided interface, enter area 0.8907, μ100, σ6, choose LEFT, then highlight Paste and press ENTER.
- Press ENTER to calculate
invNorm(0.8907,100,6,LEFT).
The source screen returns 107.3815561, so (3 s.f.). The source identifies this tail-selector interface as calculator OS 5.2.2 or higher and requires STAT WIZARDS ON. A calculator using only left cumulative probabilities can use the same area 0.8907.
(ii) Right area 0.770
The right area exceeds one half, so the cutoff must be below the mean: .
Select 3:invNorm from 2 nd VARS, enter area 0.770, μ100, σ6, choose RIGHT, then Paste, ENTER and ENTER again. The source command invNorm(0.770,100,6,RIGHT) displays 95.56691888, giving (3 s.f.).
With a left-area-only interface, first complement: , then use invNorm(0.230,100,6). Both routes describe the same cutoff.
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Common mistakes
Enter σ=6, not the variance 36. LEFT and RIGHT describe where the given area lies; a right-tail area 0.770 produces a cutoff below the mean. Sketch the area before selecting the tail.