Worked solution
Find a central eighty-percent interval
If , find such that . Hence find the limits containing the central 80% of the distribution.
CJC · Lecture · Example 3
Translate the central area
The mean is 70 and σ=5. Expand the modulus:
The bounds are equally distant from μ70. The remaining probability 0.2 splits equally into tails of 0.1.
Use either returned limit to find a
In the source’s invNorm wizard, enter area 0.8, μ70 and σ5, select CENTER, then Paste and ENTER. invNorm(0.8,70,5,CENTER) returns the pair
Either limit gives the same half-width. Using the lower limit,
Using the upper limit,
Thus (3 s.f.). Keep the full calculator values until the final rounding. If CENTER is unavailable, use LEFT areas 0.1 and 0.9 to obtain the same two limits.
State the interval limits
The central 80% lies between (3 s.f.). CENTER returns the two endpoints, not the half-width a; subtract the mean or subtract the lower endpoint from the mean to find a.
Compare your sketch
Expand diagramFit diagram to page
Use the scrollbars or arrow keys to inspect details.
Common mistakes
CENTER applies only when the desired bounds are symmetric about the mean. Do not mistake an endpoint 76.4078 for the half-width 6.4078. Use σ=√25=5.