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Worked solution

Seat ten distinct people in ten distinct seats

There are 10 vacant seats in a bus. In how many ways can 10 people seat themselves?

CJC · Lecture · Example 3

Use one seat choice for each successive person

Each person and seat is distinct, and a chosen seat is no longer available.

Person1st2nd3rd4th5th6th7th8th9th10th
Available seats10987654321
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Multiply all ten stages

Number of ways=10×9×8×⋯×1=10!=3,628,80010\times9\times8\times\cdots\times1=10!=3{,}628{,}800. Swapping two people gives a different seating arrangement.

How did this part go?

Evaluate the factorial on the source calculator

On the graphing calculator shown in the notes: type 10 in the main screen; press MATH, select PROB, then 4:!; press ENTER. The input 10! returns 3628800. These are the source menu steps; the multiplication explains the count.

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Common mistakes

Seats are distinct positions. Do not divide by 10! after counting: the identities of the people and their seats matter.

Read the hint