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Worked solution

Seat three people in ten seats without replacement

There are 10 vacant seats in a bus. In how many ways can 3 people seat themselves?

CJC · Lecture · Example 4

Use the first three seat-choice stages

Person1st2nd3rd
Available seats1098

There are 10 choices for the first person,9 for the second and 8 for the third.

How did this part go?

Recognise an ordered selection

Number of ways=10×9×8=10P3=10!/(10−3)!=72010\times9\times8={}^{10}P_3=10!/(10-3)!=720. We choose seats for three distinct people; changing who occupies a seat changes the outcome.

How did this part go?

Evaluate nPr on the source calculator

Type 10 in the main screen; press MATH, select PROB, then 2:nPr; type 3 and press ENTER. The source display 10 nPr 3 returns 720. The last step and display continue from printed page 4 onto page 5.

How did this part go?

Common mistakes

Choosing an unordered set of three seats is not enough: the three people can occupy each chosen set in 3! different ways.

Read the hint