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Worked solution

Arrange PETALS with restrictions on P and E

Find the number of ways to arrange the six letters of the word PETALS when (i) there is no restriction, (ii) P is the first letter and E is the last letter, (iii) P and E are together, (iv) P and E are separated.

CJC · Lecture · Self-Practice 5

(i) Arrange six distinct letters

There are 6!=7206!=720 arrangements.

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(ii) Fix both end letters

With P first and E last, arrange the other four distinct letters in the middle: 4!=244!=24.

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(iii) Make a block containing P and E

Arrange the block and T,A,L,S as five outer objects, then count PE and EP inside: 5!×2!=2405!\times2!=240.

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(iv) Subtract adjacent arrangements

Separated means not adjacent. Every arrangement is either adjacent or separated, giving 6!−240=720−240=4806!-240=720-240=480. The four printed answers are 720,24,240,480; these derivations supplement the answer-only Self-Practice source.

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Common mistakes

P and E may occur in either internal order when together. For separated letters use the complement of adjacency, not a fixed distance.

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