Move a reciprocal asymptote upwards

Replace y with $y-1$, giving $y-1=1/x$ and hence $y=1/x+1$. The point mapping is $(p,q)\mapsto(p,q+1)$.

Draw the original reciprocal separately from the translated graph. The shifted right branch lies above y1, and the left branch below y1, crossing the x-axis at −1 (an independent coordinate check). Transform the old horizontal asymptote with the same replacement: $y=0\mapsto y-1=0\implies y=1$. The vertical asymptote $x=0$ is independent of y and remains unchanged. The Teacher completes the translated curve label, asymptote labels and replacement stage.