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Worked solution

Read a common line from simultaneous plane equations

Find the equation of the line of intersection of r⋅(i+j−3k)=6\mathbf r\cdot(\mathbf i+\mathbf j-3\mathbf k)=6 and r⋅(2i−j+k)=4\mathbf r\cdot(2\mathbf i-\mathbf j+\mathbf k)=4.

CJC · Lecture · Example 39

Answer

r=(103,83,0)+λ(23,73,1)\mathbf r=(\frac{10}{3},\frac83,0)+\lambda(\frac23,\frac73,1), λ∈R\lambda\in\mathbb R.

Compare your reasoning

Expand the plane equations:

x+y−3z=6,2x−y+z=4.\begin{aligned}x+y-3z&=6,\\2x-y+z&=4.\end{aligned}

The source uses the calculator’s PlySmlt2 simultaneous-equation application. Its solution screen uses x1,x2,x3x_1,x_2,x_3 for x,y,zx,y,z, and displays

x=103+23z,y=83+73z,z=z.\begin{aligned}x&=\frac{10}{3}+\frac23z,\\y&=\frac83+\frac73z,\\z&=z.\end{aligned}

This can also be obtained by adding the equations to give 3x−2z=103x-2z=10, then substituting for y. Put z=λz=\lambda to read the printed base point and direction. An equivalent direction is (2,7,3)(2,7,3), with the parameter rescaled consistently. Both the base point and direction satisfy the two respective constant/direction conditions, so every point of the line is in both planes. The free third variable is essential; setting it permanently to 0 would produce only one point.

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