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Worked solution

Show the implicit slope of a trigonometric curve

A curve CC has equation y2=2sin⁡x+2xyy^2=2\sin x+2xy, where 0≤x≤2π0\leq x\leq2\pi.

Show that dydx=cos⁡x+yy−x\dfrac{dy}{dx}=\dfrac{\cos x+y}{y-x}. marks

[2022/DHS/I/5(a)]

CJC · Review Problems · Question 13

Answer

dydx=cos⁡x+yy−x\dfrac{dy}{dx}=\dfrac{\cos x+y}{y-x}.

Implicit differentiation

Differentiate: 2yy′=2cos⁡x+2(y+xy′)2yy\prime=2\cos x+2(y+xy\prime). Collecting derivative terms gives 2(y−x)y′=2(cos⁡x+y)2(y-x)y\prime=2(\cos x+y). Hence dydx=cos⁡x+yy−x\dfrac{dy}{dx}=\dfrac{\cos x+y}{y-x}, as required, where y≠xy\ne x.

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Common mistakes

The product xy contributes y as well as x dy/dx.

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