Worked solution
Score three draws without replacement
In a game, 3 red balls and 7 white balls are placed in a bag. A player draws 3 balls at random and without replacement. The player scores 2 points for every red ball that is drawn, and 1 point for every white ball that is drawn. The total score X is obtained by adding up the scores of the 3 balls.
Find the probability distribution of X. marks
Find E(X) and show that Var(X)=0.49. marks
[2017/PJC/J2MYE/II/7]
CJC · Review problems · Question 1
Answer
P(X=3,4,5,6)=(7/24,21/40,7/40,1/120); E(X)=3.9; Var(X)=0.49.
Possible scores and the combination method
| Score and colours | |
|---|---|
| 3 (3W) | |
| 4 (2W1R) | |
| 5 (1W2R) | |
| 6 (3R) |
The four source columns are displayed as rows; all compositions and probabilities are unchanged.
Alternative: sequential draws and orderings
The source also gives ; ; ; and . The factor 3 counts the position of the single differently coloured ball.
Calculate the moments
Also
Therefore , as required.
Common mistakes
Without replacement, successive colour probabilities change; this is not a binomial sample.
Solution notes
Complete distribution and both printed probability methods retained for every score, followed by both moments and variance.