Porisma

A hint to get started

Divide a rational function and integrate an inverse-tangent product

(a) Find ∫8x2+14x2−1 dx\displaystyle\int\dfrac{8x^2+1}{4x^2-1}\,dx. marks

(b) Find, using integration by parts, ∫e3xtan⁡−1(e−3x) dx\displaystyle\int e^{3x}\tan^{-1}(e^{-3x})\,dx. marks

[2013/SRJC/I/2]

CJC · Review Problems · Question 3

In (a), the numerator degree first calls for division; in (b), differentiate the inverse tangent.

Read the worked solution