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Express consecutive pair products using square and linear sums

Given ∑r=1nr2=n(n+1)(2n+1)/6\sum_{r=1}^nr^2=n(n+1)(2n+1)/6, find the sum of the first nn terms of (1)(2)+(3)(4)+(5)(6)+⋯(1)(2)+(3)(4)+(5)(6)+\cdots. marks

[2018/MI/Promo/10(b)]

CJC · Review problems · Question 5

Write one general product before applying the supplied square-sum formula.

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