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Simultaneous equations over complex numbers

Solve the following simultaneous equations:

(a) 4iz−3w=1+5i4iz-3w=1+5i and 2z+(1+i)w=2+6i2z+(1+i)w=2+6i,

(b) iz+2w=1iz+2w=1 and 4z+(3−i)w∗=−64z+(3-i)w^*=-6,

giving zz and ww in the form a+bia+bi where aa and bb are real.

CJC · Discussion · Question 4

Eliminate z first; when a conjugate remains, write w=a+bi.

Read the worked solution