Worked solution
Count products with their multiplicities before calculating moments
An unbiased regular tetrahedral die has faces 1,2,3,4. On throwing it onto a horizontal table, the face in contact with the table gives the number. Two such dice are thrown and X is the product of their numbers. Obtain the probability distribution of X, then derive
(i) ,
(ii) ,
(iii) .
[1982/II/11]
CJC · Discussion · Question 3
Answer
Distribution above; (i) ; (ii) ; (iii) .
Retain all sixteen cells of the source product table
Using independent dice, all sixteen ordered pairs are equally likely. Rows are the first die, columns the second.
| First / second | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| 1 | 1 | 2 | 3 | 4 |
| 2 | 2 | 4 | 6 | 8 |
| 3 | 3 | 6 | 9 | 12 |
| 4 | 4 | 8 | 12 | 16 |
Group equal products into the full distribution
| x | |
|---|---|
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 6 | |
| 8 | |
| 9 | |
| 12 | |
| 16 |
These nine products are not equally likely;4 has three contributing cells.
(i) Strictly above 8
.
(ii) Retain all nine expectation terms
.
(iii) Second moment and variance
. Hence .
Common mistakes
Square each possible product before averaging for the second moment. Squaring the mean gives a different quantity.
Solution notes
Initial distribution ask and all three numbered asks retained. Every source product-table cell, distribution entry and moment term retained; source independent-dice model stated. No marks printed.