Worked solution
Approximate a cube root with a binomial series
(i) Expand through and state the range of validity.
(ii) Put to approximate as in lowest terms, with .
(iii) We can also substitute into the expansion found in (i) to get an approximate value of . Explain whether this approximation is better than the approximation in (ii).
[2007/YJC/Promo/1]
CJC · Discussion · Question 6
Answer
(i) , printed range . (ii) . (iii) The printed “better” claim lacks the transformation needed to approximate the requested cube root.
(i) Expand about 8
. The printed MF27 validity condition is , giving .
(ii) Rescale the cube root
At , . Since , , in lowest terms.
(iii) Check what the substitution approximates
The printed solution answers “better” because is closer to zero. This compares local truncation for , but the stated substitution estimates , not . The source supplies no transformation between these targets, so the claimed approximation of is not established as stated. A smaller expansion variable alone does not complete this comparison.
Common mistakes
A smaller substitution improves a local approximation only after the target and scaling have been checked.