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Worked solution

Separate repeated-ball selections into disjoint cases

A box contains 8 balls, of which 3 are identical (and so are indistinguishable from one another) and the other 5 are different from each other. 3 balls are to be picked out of the box, the order in which they are picked out does not matter. Find the number of different possible selections of 3 balls.

[2006/I/4]

CJC · Discussion · Question 9

Answer

26 selections.

Three identical balls

Name the identical type I and the other balls A, B, C, D and E. Selecting I, I, I gives 1 possible selection.

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Exactly two of type I

There is 1 way to take two indistinguishable I balls and (51)=5\binom51=5 choices for the remaining distinct ball. This gives 5 selections.

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Three different types

Choose three types from A, B, C, D, E and I: (63)=20\binom63=20. This combines the cases of zero or one I without overlap. The full total is 1+5+20=261+5+20=26.

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Common mistakes

The three-different-types case may include one I. Counting it again separately would duplicate selections.

Solution notes

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