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Worked solution

Classify code words by the number of repeated pairs

Using the letters of the word CORRELATION, find the number of

(i) arrangements such that the two letters A and T are next to each other,

(ii) 6-letter code words that can be formed.

[2011/AJC/II/6(modified)]

CJC · Discussion · Question 10

Answer

(i) 1814400; (ii) 114660.

Read the available multiplicities

CORRELATION has 11 letters of 9 distinct types: O and R each occur twice; C, E, L, A, T, I and N each occur once. Letters may be used only up to these available multiplicities.

How did this part go?

(i) Group A and T

Treat A and T as one block with 2!2! internal orders. There are 10 objects, with two O’s and two R’s indistinguishable. The count is 10! 2!/(2!2!)=181440010!\,2!/(2!2!)=1814400.

How did this part go?

(ii) No repeated pair

Choose and order six distinct types from 9: 9P6=60480{}_9P_6=60480.

How did this part go?

(ii) Exactly one repeated pair

Choose which type is doubled (O or R), choose four other distinct types from the remaining 8, then arrange six letters with one pair: (21)(84) 6!/2!=50400\binom21\binom84\,6!/2!=50400. The other repeatable type may occur once here, but not twice.

How did this part go?

(ii) Both repeated pairs

Use O, O, R, R and choose two of the 7 singleton types. This gives (72) 6!/(2!2!)=3780\binom72\,6!/(2!2!)=3780. Add the three disjoint repetition patterns: 60480+50400+3780=11466060480+50400+3780=114660.

How did this part go?

Common mistakes

“9 distinct letters” in the source means 9 letter types, not 9 physical letters in the word.

Solution notes

All printed asks, working, counting factors and source annotations visually compared and retained. No marks are printed for this question.

Read the hint