A hint to get started
Deduce an infinite tail from a finite identity
Given , deduce the exact value of .
[2007/HCI/I/7(modified)]
CJC · Discussion · Question 11
An inclusive tail starting at 22 removes exactly the first 21 terms.
A hint to get started
Given ∑r=1nr(r+1)(r+2)7r+10=6−(n+15+n+22), deduce the exact value of ∑r=22∞r(r+1)(r+2)21r+30.
[2007/HCI/I/7(modified)]
CJC · Discussion · Question 11
An inclusive tail starting at 22 removes exactly the first 21 terms.