Porisma
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The binomial distribution

Practice section 5 of 7

Questions 25–30 in this collection

Practice questions

Review practice · 1 of 6

Distinguish a sample count from the position of a final success

Rose and Violet contest each other for the post of President of the Student Council of Floral Junior College. A pre-election survey indicates that Rose has the support of 45% of the school population while Violet has the support of the remaining students.

(i) Find the probability that Rose has fewer than 12 supporters in a group of 30 randomly selected students. [3]

(ii) If the students are asked to queue up to cast their votes one at a time, find the probability that the 16th student is the 10th student who votes for Violet. [3]

[2010/DHS/BT2/12(a)]

CJC · Review Problems · Question 3

See which counts the words include

(i) Fewer than 12 Rose supporters

n = 30, p = 0.45. Included counts: 0–11.

Count 0: 1.63e-8; in eventCount 1: 3.99e-7; in eventCount 2: 0.00000473; in eventCount 3: 0.0000361; in eventCount 4: 0.000200; in eventCount 5: 0.000849; in eventCount 6: 0.00289; in eventCount 7: 0.00812; in eventCount 8: 0.0191; in eventCount 9: 0.0382; in eventCount 10: 0.0656; in eventCount 11: 0.0976; in eventCount 12: 0.126; outside eventCount 13: 0.143; outside eventCount 14: 0.142; outside eventCount 15: 0.124; outside eventCount 16: 0.0953; outside eventCount 17: 0.0642; outside eventCount 18: 0.0379; outside eventCount 19: 0.0196; outside eventCount 20: 0.00882; outside eventCount 21: 0.00344; outside eventCount 22: 0.00115; outside eventCount 23: 0.000327; outside eventCount 24: 0.0000781; outside eventCount 25: 0.0000153; outside eventCount 26: 0.00000241; outside eventCount 27: 2.93e-7; outside eventCount 28: 2.57e-8; outside eventCount 29: 1.45e-9; outside eventCount 30: 3.95e-11; outside event
Count X ranges from 0 to 30. Use the inspector for individual values.

Highlighted bars form the requested event.

Solution

Review practice · 2 of 6

Count faults across two boxes rather than test each box separately

The probability that a particular make of light bulb is faulty is 0.2. The light bulbs are packed in boxes of 12.

(a) Find the probability that in a certain box, there are

(i) no faulty light bulbs

(ii) more than 3 faulty light bulbs

(b) A buyer accepts a consignment of 50 boxes, if, when he chooses two boxes at random, he finds that they contain no more than one faulty light bulb altogether. Find the probability that he will accept the consignment.

CJC · Review Problems · Question 4

See which counts the words include

(a)(i) No faults in 12

n = 12, p = 0.2. Included counts: 0–0.

Count 0: 0.0687; in eventCount 1: 0.206; outside eventCount 2: 0.283; outside eventCount 3: 0.236; outside eventCount 4: 0.133; outside eventCount 5: 0.0532; outside eventCount 6: 0.0155; outside eventCount 7: 0.00332; outside eventCount 8: 0.000519; outside eventCount 9: 0.0000577; outside eventCount 10: 0.00000433; outside eventCount 11: 1.97e-7; outside eventCount 12: 4.10e-9; outside event
Count X ranges from 0 to 12. Use the inspector for individual values.

Highlighted bars form the requested event.

Solution

Review practice · 3 of 6

Solve a rejection probability and then model accepted cartons

In a carton of apples, a sample of 8 apples is taken and examined for spoilt apples.

(i) State, in context, an assumption for the number of spoilt apples in the sample to be modelled by a binomial distribution. [1]

The number of spoilt apples in a random sample of size 8 may be modelled by the distribution B(8,p)B(8,p). If at least 2 apples in a sample are found to be spoilt, the carton is rejected. It is known that the probability of a carton being rejected is 0.04.

(ii) Write down an equation satisfied by pp and find the value of pp. [3]

(iii) 60 cartons of apples are loaded onto a lorry. Find the probability that more than 56 cartons loaded onto the lorry are not rejected. [3]

[2013/HCI/6(modified)]

CJC · Review Problems · Question 5

See which counts the words include

(ii) Reject an eight-apple sample

n = 8, p = 0.0410464741843925. Included counts: 2–8.

Count 0: 0.715; outside eventCount 1: 0.245; outside eventCount 2: 0.0367; in eventCount 3: 0.00314; in eventCount 4: 0.000168; in eventCount 5: 0.00000575; in eventCount 6: 1.23e-7; in eventCount 7: 1.51e-9; in eventCount 8: 8.06e-12; in event
Count X ranges from 0 to 8. Use the inspector for individual values.

Highlighted bars form the requested event.

Solution

Review practice · 4 of 6

Compare a binomial majority with waiting for one further red pen

A manufacturer produces pens in two colors, red and blue. On average, 35% of the pens produced are red pens.

(i) Find the probability that in a sample of 10 pens, more than half of them are red pens. [2]

(ii) The manufacturer offers a special price on red pens by selling them in packs of six. Pens are selected at random to fill each pack. Given that five red pens have been selected, find the least value of nn such that the probability that at most nn more pens need to be selected to complete a pack of 6 red pens is greater than 0.98. [4]

[2007/AJC/II/8]

CJC · Review Problems · Question 6

See which counts the words include

(i) More than five red pens

n = 10, p = 0.35. Included counts: 6–10.

Count 0: 0.0135; outside eventCount 1: 0.0725; outside eventCount 2: 0.176; outside eventCount 3: 0.252; outside eventCount 4: 0.238; outside eventCount 5: 0.154; outside eventCount 6: 0.0689; in eventCount 7: 0.0212; in eventCount 8: 0.00428; in eventCount 9: 0.000512; in eventCount 10: 0.0000276; in event
Count X ranges from 0 to 10. Use the inspector for individual values.

Highlighted bars form the requested event.

Solution

Review practice · 5 of 6

Carry a rare cap-defect tail into a box-level distribution

In a factory, a machine automatically cuts out metal caps. It is given that 0.5% of the caps are dented. Find the probability that out of 200 caps, at least 4 are dented.

A box containing 200 of such metal caps are analysed. The box is considered ‘substandard’ if it contains at least 4 dented caps. Calculate the probability that at most 6 out of 300 boxes will be ‘substandard’. [4]

[2009/SRJC/II/8(modified)]

CJC · Review Problems · Question 7

See which counts the words include

At least four dented caps

n = 200, p = 0.005. Included counts: 4–200.

Count 0: 0.367; outside eventCount 1: 0.369; outside eventCount 2: 0.184; outside eventCount 3: 0.0612; outside eventCount 4: 0.0151; in eventCount 5: 0.00298; in eventCount 6: 0.000487; in eventCount 7: 0.0000678; in eventCount 8: 0.00000822; in eventCount 9: 8.81e-7; in eventCount 10: 8.46e-8; in eventCount 11: 7.34e-9; in eventCount 12: 5.81e-10; in eventCount 13: 4.22e-11; in eventCount 14: 2.83e-12; in eventCount 15: 1.77e-13; in eventCount 16: 1.03e-14; in eventCount 17: 5.58e-16; in eventCount 18: 2.85e-17; in eventCount 19: 1.37e-18; in eventCount 20: 6.24e-20; in eventCount 21: 2.69e-21; in eventCount 22: 1.10e-22; in eventCount 23: 4.28e-24; in eventCount 24: 1.58e-25; in eventCount 25: 5.61e-27; in eventCount 26: 1.90e-28; in eventCount 27: 6.14e-30; in eventCount 28: 1.91e-31; in eventCount 29: 5.68e-33; in eventCount 30: 1.63e-34; in eventCount 31: 4.48e-36; in eventCount 32: 1.19e-37; in eventCount 33: 3.04e-39; in eventCount 34: 7.51e-41; in eventCount 35: 1.79e-42; in eventCount 36: 4.13e-44; in eventCount 37: 9.19e-46; in eventCount 38: 1.98e-47; in eventCount 39: 4.13e-49; in eventCount 40: 8.36e-51; in eventCount 41: 1.64e-52; in eventCount 42: 3.12e-54; in eventCount 43: 5.76e-56; in eventCount 44: 1.03e-57; in eventCount 45: 1.80e-59; in eventCount 46: 3.05e-61; in eventCount 47: 5.02e-63; in eventCount 48: 8.03e-65; in eventCount 49: 1.25e-66; in eventCount 50: 1.90e-68; in eventCount 51: 2.81e-70; in eventCount 52: 4.04e-72; in eventCount 53: 5.68e-74; in eventCount 54: 7.76e-76; in eventCount 55: 1.04e-77; in eventCount 56: 1.35e-79; in eventCount 57: 1.71e-81; in eventCount 58: 2.12e-83; in eventCount 59: 2.56e-85; in eventCount 60: 3.03e-87; in eventCount 61: 3.49e-89; in eventCount 62: 3.93e-91; in eventCount 63: 4.33e-93; in eventCount 64: 4.66e-95; in eventCount 65: 4.90e-97; in eventCount 66: 5.03e-99; in eventCount 67: 5.06e-101; in eventCount 68: 4.97e-103; in eventCount 69: 4.78e-105; in eventCount 70: 4.49e-107; in eventCount 71: 4.14e-109; in eventCount 72: 3.72e-111; in eventCount 73: 3.28e-113; in eventCount 74: 2.83e-115; in eventCount 75: 2.39e-117; in eventCount 76: 1.97e-119; in eventCount 77: 1.60e-121; in eventCount 78: 1.27e-123; in eventCount 79: 9.82e-126; in eventCount 80: 7.47e-128; in eventCount 81: 5.56e-130; in eventCount 82: 4.05e-132; in eventCount 83: 2.90e-134; in eventCount 84: 2.03e-136; in eventCount 85: 1.39e-138; in eventCount 86: 9.34e-141; in eventCount 87: 6.15e-143; in eventCount 88: 3.97e-145; in eventCount 89: 2.51e-147; in eventCount 90: 1.56e-149; in eventCount 91: 9.45e-152; in eventCount 92: 5.63e-154; in eventCount 93: 3.28e-156; in eventCount 94: 1.88e-158; in eventCount 95: 1.05e-160; in eventCount 96: 5.79e-163; in eventCount 97: 3.12e-165; in eventCount 98: 1.65e-167; in eventCount 99: 8.53e-170; in eventCount 100: 4.33e-172; in eventCount 101: 2.15e-174; in eventCount 102: 1.05e-176; in eventCount 103: 5.02e-179; in eventCount 104: 2.35e-181; in eventCount 105: 1.08e-183; in eventCount 106: 4.87e-186; in eventCount 107: 2.15e-188; in eventCount 108: 9.30e-191; in eventCount 109: 3.94e-193; in eventCount 110: 1.64e-195; in eventCount 111: 6.68e-198; in eventCount 112: 2.67e-200; in eventCount 113: 1.04e-202; in eventCount 114: 4.00e-205; in eventCount 115: 1.50e-207; in eventCount 116: 5.54e-210; in eventCount 117: 2.00e-212; in eventCount 118: 7.07e-215; in eventCount 119: 2.45e-217; in eventCount 120: 8.30e-220; in eventCount 121: 2.76e-222; in eventCount 122: 8.97e-225; in eventCount 123: 2.86e-227; in eventCount 124: 8.92e-230; in eventCount 125: 2.73e-232; in eventCount 126: 8.15e-235; in eventCount 127: 2.39e-237; in eventCount 128: 6.84e-240; in eventCount 129: 1.92e-242; in eventCount 130: 5.27e-245; in eventCount 131: 1.41e-247; in eventCount 132: 3.71e-250; in eventCount 133: 9.54e-253; in eventCount 134: 2.40e-255; in eventCount 135: 5.89e-258; in eventCount 136: 1.41e-260; in eventCount 137: 3.32e-263; in eventCount 138: 7.62e-266; in eventCount 139: 1.71e-268; in eventCount 140: 3.74e-271; in eventCount 141: 8.00e-274; in eventCount 142: 1.67e-276; in eventCount 143: 3.40e-279; in eventCount 144: 6.77e-282; in eventCount 145: 1.31e-284; in eventCount 146: 2.49e-287; in eventCount 147: 4.59e-290; in eventCount 148: 8.26e-293; in eventCount 149: 1.45e-295; in eventCount 150: 2.47e-298; in eventCount 151: 4.12e-301; in eventCount 152: 6.67e-304; in eventCount 153: 1.05e-306; in eventCount 154: 1.61e-309; in eventCount 155: 2.41e-312; in eventCount 156: 3.49e-315; in eventCount 157: 4.91e-318; in eventCount 158: 6.72e-321; in eventCount 159: 8.91e-324; in eventCount 160: 1.15e-326; in eventCount 161: 1.43e-329; in eventCount 162: 1.73e-332; in eventCount 163: 2.03e-335; in eventCount 164: 2.30e-338; in eventCount 165: 2.52e-341; in eventCount 166: 2.67e-344; in eventCount 167: 2.74e-347; in eventCount 168: 2.70e-350; in eventCount 169: 2.57e-353; in eventCount 170: 2.36e-356; in eventCount 171: 2.08e-359; in eventCount 172: 1.76e-362; in eventCount 173: 1.43e-365; in eventCount 174: 1.12e-368; in eventCount 175: 8.33e-372; in eventCount 176: 5.95e-375; in eventCount 177: 4.05e-378; in eventCount 178: 2.63e-381; in eventCount 179: 1.62e-384; in eventCount 180: 9.52e-388; in eventCount 181: 5.29e-391; in eventCount 182: 2.77e-394; in eventCount 183: 1.37e-397; in eventCount 184: 6.37e-401; in eventCount 185: 2.77e-404; in eventCount 186: 1.12e-407; in eventCount 187: 4.22e-411; in eventCount 188: 1.47e-414; in eventCount 189: 4.68e-418; in eventCount 190: 1.36e-421; in eventCount 191: 3.58e-425; in eventCount 192: 8.43e-429; in eventCount 193: 1.76e-432; in eventCount 194: 3.18e-436; in eventCount 195: 4.92e-440; in eventCount 196: 6.31e-444; in eventCount 197: 6.44e-448; in eventCount 198: 4.90e-452; in eventCount 199: 2.48e-456; in eventCount 200: 6.22e-461; in event
Count X ranges from 0 to 200. Use the inspector for individual values.

Highlighted bars form the requested event.

Solution

Review practice · 6 of 6

Carry an underweight-chocolate event into a box count

A factory produces chocolate which are packed into boxes of 20 and delivered to shops for sale. A chocolate will not meet the minimum criteria for packing for sale if it weighs less than 20 grams. On average, 2% of the chocolate produced did not meet the minimum criteria.

(i) Find the probability that a randomly chosen box contain at least 1 chocolate that does not meet the minimum criteria. [2]

(ii) Find the probability that out of 4 randomly chosen boxes of chocolate, there are exactly 2 boxes with at least 1 chocolate that does not meet the minimum criteria. [2]

[2007/TPJC/II/5]

CJC · Review Problems · Question 8

See which counts the words include

(i) At least one underweight chocolate

n = 20, p = 0.02. Included counts: 1–20.

Count 0: 0.668; outside eventCount 1: 0.272; in eventCount 2: 0.0528; in eventCount 3: 0.00647; in eventCount 4: 0.000561; in eventCount 5: 0.0000366; in eventCount 6: 0.00000187; in eventCount 7: 7.63e-8; in eventCount 8: 2.53e-9; in eventCount 9: 6.89e-11; in eventCount 10: 1.55e-12; in eventCount 11: 2.87e-14; in eventCount 12: 4.39e-16; in eventCount 13: 5.51e-18; in eventCount 14: 5.63e-20; in eventCount 15: 4.59e-22; in eventCount 16: 2.93e-24; in eventCount 17: 1.41e-26; in eventCount 18: 4.78e-29; in eventCount 19: 1.03e-31; in eventCount 20: 1.05e-34; in event
Count X ranges from 0 to 20. Use the inspector for individual values.

Highlighted bars form the requested event.

Solution

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