Techniques of differentiation
Understand limits and derivatives · Diagrams · Complete reading
Read the same limit from a curve and a table
Approach the same limit from both sides
For f(x) = x² − x + 2, move towards x = 2 and compare the curve with the table. Here f(2) = 4 as well as the limit being 4.
Nearby values illustrate the limit; a finite table alone is not a proof.
Teaching and source notes
The retained source uses f(x) = x² − x + 2 and approaches x = 2 from both sides. Substitution gives f(2) = 4. Polynomial continuity justifies this limit; a small table alone is not its proof.
The approach control never substitutes h = 0. Rounded nearby function values need not equal 4 exactly, even when the display rounds them to 4. The linked original retains the printed guide projections.
Distinguish a missing value from a missing limit
A missing value can still have a limit
Use radians. The curve sin(x)/x approaches 1 from both sides, but no function value is assigned at x = 0. The open circle stays open.
Nearby values illustrate the limit; a finite table alone is not a proof.
Teaching and source notes
The source graph has an open circle at (0, 1). No value is assigned to sin(x)/x at x = 0, and the explorer keeps a gap in the curve there. The two-sided limit is 1 when x is measured in radians.
The approach table supports comparison; it is not a proof. Establishing this standard limit requires an argument such as the squeeze theorem. A rounded value of 1 does not remove the domain hole.
Let a secant approach a tangent
Move a secant towards the tangent
Illustrative example: y = x² with P = (1, 1). Move Q = (1 + h, (1 + h)²) towards P. The source sketch uses a general smooth curve, not this particular formula.
Nearby values illustrate the limit; a finite table alone is not a proof.
Teaching and source notes
The source sketch is a general smooth curve with P(x, y), Q(x + h, y + Δy), secant PQ and tangent AB. This numerical example is explicitly y = x² at P = (1, 1), not a recovered formula for the original drawing.
For h ≠ 0, Δy = (1 + h)² − 1 = h(2 + h), so Δy/h = 2 + h. Its limit is 2 from either side. At h = 0 the difference quotient is undefined; the derivative comes from its limit. A secant need not tend to a tangent where the derivative does not exist.