Applications of differentiation
Learn one idea at a time
Choose a unit. Each has worked examples and practice.
Classify stationary points
Use derivative tests and explain when a stationary point is not a turning point.
Read curve shape and derivative graphs
Connect slope, concavity and inflection to a derivative sketch.
Find tangents and normals
Use the derivative and a specified point to form the required line.
Connect changing quantities
Build and solve an optimisation model
Form the quantity to optimise and check that the stationary value is valid.
By the end, you can
- Connect derivative signs to increasing and decreasing behaviour
- Classify stationary points and find tangents
- Model optimisation and connected rates
5 focused units · about 40 minutes for the full chapter. Allow extra time for practice.
The central idea
The first derivative gives slope and the second describes how that slope changes. Stationary points satisfy f′(x)=0, but their nature needs a sign change or another test. In optimisation, reduce the quantity to one variable, preserve the physical domain, and compare candidates with boundaries. Connected rates differentiate a relation with respect to time.
Increasing versus strictly increasing
On an interval I, for every , increasing means and strictly increasing means . Decreasing and strictly decreasing reverse those inequalities to and .
If f is differentiable and throughout I, f is strictly increasing there; a negative derivative throughout gives strict decrease. The source curve increases on and and decreases on . These are sufficient tests: strict increase can still allow an isolated zero derivative, as with at zero.
Why applications need a model
The source introduces uses in physics (motion, electricity, heat, light, harmonics, acoustics, astronomy and dynamics), chemistry (reaction rates and radioactive decay), biology (birth/death rates), economics (marginal cost/revenue and profit), engineering, statistics and medicine.
Its supermarket example asks how to choose the height-to-diameter ratio of a cylindrical can to minimise manufacturing surface area at fixed volume.
The original can photograph is retained in the source archive, with its printed DataGenetics attribution; the linked external page has not been reviewed.
The full chapter outline also includes interpreting first/second derivative signs, relating a function’s graph to its derivative’s graph, tangents/normals including implicit curves, calculator extrema, analytical classification, optimisation and connected rates. The complete lecture now connects these ideas through sixteen examples, three self-practices, source diagrams and the linked Discussion/Review questions.
Worked example
A rectangular pen stands against a straight wall, so 24 m of fencing is used for its other three sides. Let be each side perpendicular to the wall and the remaining side.
The constraint is and the area is , with . Thus , giving and .
The derivative is positive before 6 and negative after 6 on the feasible domain.
Together with area tending to zero at both ends, this establishes the greatest area of .
A stationary value is a candidate. Check the physical domain and allowed endpoints or limiting boundary behaviour before claiming an overall optimum.
Check your understanding
An open box is made from a 24 cm square sheet by cutting a square of side cm from each corner and folding up the four sides. Construct a model and find the greatest possible volume. State the feasible domain and justify that your dimensions give the greatest volume, rather than merely a stationary value.
The height is and each base side is , so for . Differentiation gives . The interior stationary input is ; would produce a degenerate box and is outside the domain.
The derivative is positive on and negative on , while volume tends to zero at both domain ends. Thus the greatest volume is , with base 16 cm by 16 cm and height 4 cm.
Practice questions
44 examples and practice questions, in 8 sections.
More practice
Draw the situation and define the quantities before choosing a derivative. Check units, the feasible domain and the justification for the requested maximum, minimum or rate.
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