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Review practice · Section 2 of 3

Questions 7–12 in this collection

Apply double-angle and product-to-sum identities before integrating · Complete a square after substitution and use a product derivative · +4 more

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  1. 7

    Find the following integrals:

    (a) ∫11+cos⁡4θ dθ\displaystyle\int\dfrac1{1+\cos4\theta}\,d\theta, marks

    (b) ∫cos⁡2xsin⁡3x dx\displaystyle\int\cos2x\sin3x\,dx, given 2sin⁡Acos⁡B=sin⁡(A+B)+sin⁡(A−B)2\sin A\cos B=\sin(A+B)+\sin(A-B). marks

    [2016/NYJC/Promo/3 modified]

    CJC · Review Problems · Question 7

  2. 8

    (a) By using the substitution u=xu=\sqrt x, find ∫1x (x+2x+2) dx\displaystyle\int\dfrac1{\sqrt x\,(x+2\sqrt x+2)}\,dx. marks

    (b) Find ddx(xsin⁡x)\dfrac d{dx}(x\sin x). mark

    Hence find ∫(sin⁡x+xcos⁡x)ln⁡x dx\displaystyle\int(\sin x+x\cos x)\ln x\,dx. marks

    [2016/PJC/Promo/7]

    CJC · Review Problems · Question 8

  3. 9

    Use the substitution u=cos⁡2θu=\cos2\theta to find ∫sin⁡2θ4−cos⁡22θ dθ\displaystyle\int\dfrac{\sin2\theta}{4-\cos^22\theta}\,d\theta. marks

    [2018/DHS/Promo/1(b)]

    CJC · Review Problems · Question 9

  4. 10

    (i) Find ∫etan⁡−12x1+4x2 dx\displaystyle\int\dfrac{e^{\tan^{-1}2x}}{1+4x^2}\,dx. marks

    (ii) Given that −π2<θ<π2-\dfrac\pi2<\theta<\dfrac\pi2, use the substitution x=sin⁡θx=\sin\theta to find ∫x21−x2 dx\displaystyle\int\dfrac{x^2}{\sqrt{1-x^2}}\,dx. marks

    [2018/MI/Promo/PU2/I/9]

    CJC · Review Problems · Question 10

  5. 11

    Find the following integrals:

    (a) ∫e2xe2x−3 dx\displaystyle\int\dfrac{e^{2x}}{e^{2x}-3}\,dx marks

    (b) ∫3x2+2x3+2x−8 dx\displaystyle\int\dfrac{3x^2+2}{\sqrt{x^3+2x-8}}\,dx marks

    (c) ∫1x2+2x+5 dx\displaystyle\int\dfrac1{x^2+2x+5}\,dx marks

    (d) ∫x2ln⁡x dx\displaystyle\int x^2\ln x\,dx marks

    (e) ∫xsec⁡(x2)tan⁡(x2) dx\displaystyle\int x\sec(x^2)\tan(x^2)\,dx marks

    [2018/MJC/Promo/2(modified)]

    CJC · Review Problems · Question 11

  6. 12

    Express x+3=A(2x+2)+Bx+3=A(2x+2)+B, where AA and BB are constants to be determined.

    Hence, find ∫x+3x2+2x+2 dx\displaystyle\int\dfrac{x+3}{x^2+2x+2}\,dx. marks

    [2019/RVHS/Promo/4(a)]

    CJC · Review Problems · Question 12

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