Porisma

A hint to get started

Separate odd-index and even-index denominator terms

Given An=∑r=1n1/[r(r+2)]=3/4−1/[2(n+1)]−1/[2(n+2)]A_n=\sum_{r=1}^n1/[r(r+2)]=3/4-1/[2(n+1)]-1/[2(n+2)]:

(i) Deduce An<3/4A_n<3/4 for all positive integers nn. mark

(ii) Given also ∑r=1n1/[r(r+1)]=1−1/(n+1)\sum_{r=1}^n1/[r(r+1)]=1-1/(n+1), find ∑r=1n1/[2r(2r+2)]\sum_{r=1}^n1/[2r(2r+2)]. marks

(iii) Use these results to find ∑r=1n1/(4r2−1)\sum_{r=1}^n1/(4r^2-1) in terms of nn. marks

[2012/VJC/Promo/13(modified)]

CJC · Review problems · Question 8

Use A at 2n so that its terms contain exactly n odd indices and n even indices.

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