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A hint to get started

Use two distinct real roots to restrict a parameter

The numbers xx and yy satisfy the equation

4x2+16xy+y2+16x+14y+13=04x^2+16xy+y^2+16x+14y+13=0.

If a real value of xx is substituted, the equation becomes a quadratic equation in yy. Given that two distinct real values of yy may be found from this equation, show that

5x2+8x+3>05x^2+8x+3>0,

and hence find the set of possible values of xx.

[2004/I/5]

CJC · Review Problems · Question 15

Treat y as the quadratic variable and x as a parameter; distinct real roots require a strictly positive discriminant.

Read the worked solution