Porisma

A hint to get started

Turn a cross product with a unit direction into a distance

Referred to O, OA=aOA=\mathbf a, OB=bOB=\mathbf b. C lies on OA with OC:CA=1:2; D lies on OB with OD:DB=2:3. M is the midpoint of CD.

(i) Find OM in terms of a,b and show that the area of triangle OMD is k∣a×b∣k|\mathbf a\times\mathbf b|, finding k. marks

(ii) Now a=2i+3j+6k\mathbf a=2\mathbf i+3\mathbf j+6\mathbf k, b=10i+5j+10k\mathbf b=10\mathbf i+5\mathbf j+10\mathbf k. Find OM→×b^\overrightarrow{OM}\times\widehat{\mathbf b} and give the geometrical meaning of its magnitude. marks

[2016/SRJC/Promo/6]

CJC · Review problems · Question 14

Normalise b before taking the cross product required in(ii).

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