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Worked solution

Reduce a differential equation with a substitution

Show that y=ux2y=ux^2 reduces x2dydx−2xy+y2=0x^2\dfrac{dy}{dx}-2xy+y^2=0, where x>0x>0, to dudx+u2=0\dfrac{du}{dx}+u^2=0. Hence show that the general solution may be expressed as y=x2/(C+x)y=x^2/(C+x), with arbitrary constant CC.

[2006/TJC/I/14(OR)(modified)]

CJC · Discussion · Question 2

Answer

y=x2/(x+C)y=x^2/(x+C) on admissible intervals, together with the additional solution y=0y=0.

Apply the product rule

y=ux2y=ux^2 gives y′=2ux+x2u′y^\prime=2ux+x^2u^\prime. Substitution gives x2(2ux+x2u′)−2x(ux2)+u2x4=x4(u′+u2)=0x^2(2ux+x^2u^\prime)-2x(ux^2)+u^2x^4=x^4(u^\prime+u^2)=0. Since x>0x>0, u′+u2=0u^\prime+u^2=0.

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Separate the nonzero solution

For u≠0u\ne0, −u−2 du=dx-u^{-2}\,du=dx, so 1/u=x+C1/u=x+C. Returning to yy gives y=x2/(x+C)y=x^2/(x+C) on intervals with x>0x>0 and x+C≠0x+C\ne0.

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Retain the equilibrium lost by division

u=0u=0 also solves the reduced equation, giving y=0y=0 in the original equation. This valid solution is omitted by division by u2u^2 and is not represented by a finite value of CC in the printed family.

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Common mistakes

Dividing by a dependent variable can lose an equilibrium solution.

Read the hint