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Reflect the origin across an equal-radius chord

The points AA and BB have position vectors a\mathbf a and b\mathbf b respectively, relative to the origin OO such that ∣a∣=∣b∣|\mathbf a|=|\mathbf b|. The point PP with position vector p\mathbf p lies on ABAB such that b⋅p=a⋅p\mathbf b\cdot\mathbf p=\mathbf a\cdot\mathbf p.

(i) Show that AB→\overrightarrow{AB} is perpendicular to OP→\overrightarrow{OP}.

(ii) Determine the position vector of the point DD in terms of a\mathbf a and b\mathbf b, where DD is the reflection of OO about the line ABAB.

(iii) Give the geometrical meaning of ∣a×b∣|\mathbf a\times\mathbf b|.

[2010/NJC/I/3]

CJC · Discussion · Question 10

Equal distances OA and OB make the perpendicular foot the midpoint of AB.

Read the worked solution