Porisma

A hint to get started

Use two line parameters, a division ratio and a cross-product area

With reference to an origin OO, the points AA, BB, CC and DD are such that OA→=a\overrightarrow{OA}=\mathbf a, OB→=b\overrightarrow{OB}=\mathbf b, OC→=3a−b\overrightarrow{OC}=3\mathbf a-\mathbf b and OD→=2a+3b\overrightarrow{OD}=2\mathbf a+3\mathbf b. The lines BCBC and ADAD intersect at point XX (see diagram).

(i) Express OX→\overrightarrow{OX} in terms of a\mathbf a and b\mathbf b.

(ii) The point YY on BCBC is such that BY:YC=2:11BY:YC=2:11. Show that the points OO, YY and DD are collinear.

(iii) Find the ratio of the area of triangle OABOAB to the area of triangle BCDBCD.

Expand diagram

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O is the origin; OA=a and OB=b are nonparallel. C has position 3a-b and D has position 2a+3b. Segments BC and AD meet at X. Coordinates in this independent planar embedding illustrate the vector relations only; they are not additional numerical data.
O is the origin; OA=a and OB=b are nonparallel. C has position 3a-b and D has position 2a+3b. Segments BC and AD meet at X. Coordinates in this independent planar embedding illustrate the vector relations only; they are not additional numerical data.
O is the origin; OA=a and OB=b are nonparallel. C has position 3a-b and D has position 2a+3b. Segments BC and AD meet at X. Coordinates in this independent planar embedding illustrate the vector relations only; they are not additional numerical data.

[2022/RVHS/J2MYE/I/3]

CJC · Discussion · Question 9

Compare a and b coefficients only because their directions are independent in the source diagram.

Read the worked solution