Porisma

Review practice · Section 2 of 2

Questions 7–9 in this collection

Connect a derivative discriminant to the missing range · Use completing the square before drawing a rational graph · +1 more

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  1. 7

    · Techniques of Differentiation

    C:y=(x2+a)/(x−a)C:y=(x^2+a)/(x-a), x≠a, where a is a non-zero constant.

    (i) Given the oblique asymptote y=x+2, find a. mark

    (ii) Find the set of values of a if C has two turning points. marks

    (iii) Using a from (i) and an algebraic method, show C cannot exist for y₁<y<y₂, determining y₁,y₂ exactly. marks

    (iv) Hence sketch C, clearly showing the asymptotes and stationary-point coordinates. marks

    [2010/NYJC/Promo/10]

    CJC · Review problems · Question 7

  2. 8

    C:y=f(x)C:y=f(x) where f(x)=(4x2+bx+c)/(4x+8)f(x)=(4x^2+bx+c)/(4x+8) and b,c are real constants. C has oblique asymptote y=x−5.

    (i) Find b. marks

    (ii) Given c>9, show C does not cut the x-axis. mark

    (iii) For c=13 sketch C, clearly indicating asymptotes, axial intercepts and turning points. marks

    [2012/SRJC/Promo/8]

    CJC · Review problems · Question 8

  3. 9

    C:y=(−2x2−2x+a)/(x+1)C:y=(-2x^2-2x+a)/(x+1), where a is a non-zero constant. C exists for y≤−2 or y≥b, where b is positive.

    (i) Using an analytical method, show a=−2 and hence find b. marks

    (ii) Sketch C, clearly showing turning-point coordinates and asymptotes. marks

    (iii) Show(−3,6) lies on y=px+3 p+6 for every real p. Hence use the sketch in(ii) to find p for which px+3p+6=(−2x2−2x−2)/(x+1)px+3p+6=(-2x^2-2x-2)/(x+1) has two distinct real roots. marks

    [2015/SRJC/MYE/9]

    CJC · Review problems · Question 9

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