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The normal distribution

Practice section 3 of 7

Questions 13–18 in this collection

Practice questions

Worked example · 2 of 6

Distinguish two children from twice one child

In a country, men’s weights are normal with mean 70 kg and variance 18 kg², and children’s weights are normal with mean 30 kg and variance 9 kg². The weights of men and children are independent. Find the probability that

(i) a randomly selected man weighs more than two randomly selected children combined,

(ii) a randomly selected man weighs more than twice one randomly selected child. A certain HDB lift has maximum load 340 kg:

(iii) find the probability it is overloaded by 3 men and 4 children;

(iv) find the smallest a such that the probability that the average weight of three randomly chosen men exceeds a kg is less than 0.7.

CJC · Lecture · Example 8

Solution

Worked example · 3 of 6

Apply prices after adding independent masses

Melons cost $1.50 per kilogram and their masses are normal with mean 0.8 kg and standard deviation 0.1 kg. Pumpkins cost $0.50 per kilogram and their masses are normal with mean 1.2 kg and standard deviation 0.2 kg. Find the probability that the total price of 5 randomly chosen melons and 3 randomly chosen pumpkins exceeds $8.

[N2002/II/28]

CJC · Lecture · Example 9

Solution

Worked example · 4 of 6

Match height questions to the correct probability model

In a nation, men’s heights are normal with mean 1.70 m and standard deviation 10 cm; women’s heights are normal with mean 1.60 m and standard deviation 7.5 cm.

(i) Three men are selected at random: find the probability that one is taller than 1.83 m, one is shorter than 1.7 m and the other is between 1.7 m and 1.83 m.

(ii) Five men are selected at random: find the probability that exactly 3 are taller than 1.83 m.

(iii) Find the probability that the average height of 3 men and 2 women chosen randomly exceeds 1.68 m.

(iv) Find the probability that a husband and wife have not more than 5 cm difference in heights.

(v) State the assumptions made for (iii) and (iv).

CJC · Lecture · Example 10

Solution

Discussion practice · 6 of 6

Check the normal model against the possible mark range

An examination is marked out of 100 and taken by a large number of candidates. The mean mark is 72.1 and standard deviation 15.2. Give a reason why a normal distribution with this mean and standard deviation would not give a good approximation to the marks.

[2008/H1/7(a)]

CJC · Discussion · Question 2

Solution

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