Porisma

Review practice · Section 1 of 2

Questions 1–6 in this collection

Eliminate t using a cancelling linear combination · Eliminate a positive parameter and retain closed endpoints · +4 more

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  1. 1

    Find the cartesian equation of the curve with parametric equations: x=−4t−1tx=-4t-\dfrac1t, y=3t+12ty=3t+\dfrac1{2t}. marks

    [2008/CJC/JC1/MYE/2]

    CJC · Review problems · Question 1

  2. 2

    The curve CC is defined by x=t2x=t^2, y=ln⁡ty=\ln t, t>0t>0.

    (i) Sketch CC for 2≤x≤52\le x\le5, indicating the coordinates of the endpoints. marks

    (ii) Find the cartesian equation of CC. marks

    [2009/ACJC/II/3(modified)]

    CJC · Review problems · Question 2

  3. 3

    (a) Find the cartesian equation for x=cos⁡θx=\cos\theta, y=2sin⁡2θy=2\sin^2\theta. marks

    (b) A curve has x=t3+tx=t^3+t, y=2t−1y=2t-1, −1≤t≤1-1\le t\le1.

    (i) Sketch the curve, indicating its axial intercepts. marks

    (ii) Without using a calculator, find its intersection with y=12y=\tfrac12. marks

    [2010/CJC/MYE/2(modified)]

    CJC · Review problems · Question 3

  4. 4

    A curve has x=t/(1+t)x=t/(1+t), y=ln⁡(cos⁡t)y=\ln(\cos t), where the printed exclusions are t≠−1,π/2t\ne-1,\pi/2. Find dy/dxdy/dx in terms of tt. marks

    [2009/CJC/Promo/10(a)]

    CJC · Review problems · Question 4

  5. 5

    A curve has x=3t−1/tx=3t-1/t, y=t+4/(3t)y=t+4/(3t). Find the exact value(s) of tt at which the gradient is 1/61/6. marks

    [2008/YJC/Promo/12(a)]

    CJC · Review problems · Question 5

  6. 6

    The curve CC has x=t2(t+6)x=t^2(t+6), y=t2+t−6y=t^2+t-6, t<0t<0.

    (i) Find the equation(s) of the tangent to CC parallel to the y-axis. marks

    (ii) Sketch CC, showing its axial intercepts. marks

    [2018/NYJC/I/8(i)&(ii)]

    CJC · Review problems · Question 6

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