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Sampling and the sample mean

Practice section 2 of 5

Questions 7–12 in this collection

Practice questions

Worked example · 2 of 6

Approximate mean daily wine production

A vineyard produces an average of 400 barrels of wine per day, with standard deviation 70.

(a) For a random sample of 50 days’ production, is Xˉ\bar X normally distributed? Explain briefly and state its mean and variance.

(b) Find the probability that the sample mean is more than 380.

CJC · Lecture · Example 8

Solution

Worked example · 3 of 6

Compare two independent sample means

Two firms A and B manufacture components with mean breaking strengths 6 kN and 5.5 kN and standard deviations 0.4 kN and 0.2 kN respectively. Random samples of 100 components from A and 50 from B are tested. Find the probability that the mean strength from A is between 0.45 kN and 0.55 kN more than that from B.

CJC · Lecture · Example 9

Solution

Worked example · 4 of 6

Estimate a population, then qualify a plug-in tail probability

The distance between a pupil’s home and school is xx km. A random sample of 60 pupils gives ∑x=33.6\sum x=33.6 and ∑x2=22.79\sum x^2=22.79. Calculate unbiased estimates of the population mean and variance.

Estimate the probability that the mean value of xx, for this sample, will be less than 0.5. State any assumptions or approximations used.

CJC · Lecture · Example 10

Solution

Discussion practice · 6 of 6

Use raw and shifted summaries for unbiased estimates

Find unbiased estimates of the population mean and variance from each sample.

(a) ∑x=15508\sum x=15508, ∑x2=2413891\sum x^2=2413891, n=100n=100.

(b) ∑(t−36.9)=−12\sum(t-36.9)=-12, ∑(t−36.9)2=79.21\sum(t-36.9)^2=79.21, n=40n=40.

CJC · Discussion · Question 2

Solution

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