Porisma

Review practice · Section 4 of 4

Questions 19–22 in this collection

Combine geometric heights with a weighted class mean · Compare a geometric training total with an arithmetic total · +2 more

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  1. 19

    A class has 1616 boys with AP heights and 1010 girls with GP heights. The shortest boy and girl are each 150.0150.0 cm. The tallest boy is 180.0180.0 cm, and the fourth-shortest girl is 157.5157.5 cm.

    (i) Show the girls’ common ratio is 1.051/31.05^{1/3} and find the tallest girl’s height to 1 d.p. marks

    (ii) Find how many girls are taller than 164.0164.0 cm. marks

    (iii) Find the girls’ mean height to 1 d.p. marks

    (iv) Find the class mean to 1 d.p. marks

    [2013/NYJC/Promo/9]

    CJC · Review problems · Question 19

  2. 20

    (i) Swimmer A swims 5050 m on day one and increases each subsequent day’s distance by 10%10\% of the previous day’s distance for 3030 days.

    (a) Show her day-30 distance is 793793 m to the nearest metre. marks

    (b) Find her total in 30 days to the nearest metre. marks

    (ii) Swimmer B starts at 5050 m and adds 55 m each day. Find the least number of days for B’s total to exceed A’s total in (i)(b). marks

    [2012/TPJC/Promo/7]

    CJC · Review problems · Question 20

  3. 21

    A grain facility holds 1000010000 bushels at the end of December 2013. Insurance pay-outs purchase extra grain, increasing the stock by 2%2\% before the end of every month.

    (a) Find the stock at the end of December 2014. mark

    (b) During January–December 2014 the facility supplies x bushels to a laboratory each month, before the 2%2\% addition.

    (i) For x=100x=100, show the end-March stock is 10299.910299.9 bushels to 1 d.p. marks

    (ii) Find the maximum monthly supply. marks

    [2014/HCI/Promo/6]

    CJC · Review problems · Question 21

  4. 22

    A man enters a coma after an accident on 10 January 2013 and misses payment of his credit-card balance M dollars due on 27 January. On each monthly 27th, unpaid balances first receive 2%2\% interest and then an additional late fee L dollars.

    (a) Express his balance on 1 February 2013 in terms of M and L. mark

    (b) Show that exactly n months after the accident, on the same day of the month, the accumulated balance is (1.02)nM+50L[(1.02)n−1](1.02)^nM+50L[(1.02)^n-1]. marks

    (c) For M=1000M=1000, L=55L=55, find the least n for which the balance first exceeds $2010. marks

    [2013/AJC/Promo/15]

    CJC · Review problems · Question 22

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