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Balance constant inflow against volume-dependent outflow

A tank initially contains 2 m32\,\mathrm{m}^3. Water enters at 4 m3s−14\,\mathrm{m}^3\mathrm{s}^{-1} and leaves at a rate proportional to the volume VV. When V=6 m3V=6\,\mathrm{m}^3, the net rate is 1 m3s−11\,\mathrm{m}^3\mathrm{s}^{-1}. Set up and solve a differential equation to show V=8−6e−0.5tV=8-6e^{-0.5t}. marks

(i) Describe what happens to the volume eventually. mark

(ii) Sketch VV against tt. marks

[2013/MJC/I/7]

CJC · Review problems · Question 9

The given rate at V=6 is the net change, not the outflow by itself.

Read the worked solution