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Optimise corner flower crates around a central pond

A square lawn ABCDABCD has side 2626 m and a circular pond of radius 1111 m centred at its centre PP. A rectangular flower crate QTCSQTCS has corner CC at the square corner and opposite corner QQ on the pond. Let RR be the midpoint of DCDC on the downward centre line. The angle RPQ=θRPQ=\theta is measured from PRPR, with 0≤θ≤π/40\le\theta\le\pi/4. Its base area is X m2X\text{ m}^2.

(i) Express XX in terms of θ\theta and show dX/dθ=11(sin⁡θ−cos⁡θ)(13−11sin⁡θ−11cos⁡θ)dX/d\theta=11(\sin\theta-\cos\theta)(13-11\sin\theta-11\cos\theta). marks

(ii) For stationary values, show the angles satisfy tan⁡θ1=1\tan\theta_1=1 and sin⁡(θ2+α)=k\sin(\theta_2+\alpha)=k, where k,αk,\alpha are exact constants. Find θ1,θ2\theta_1,\theta_2. marks

(iii) Classify both stationary values and find their areas. marks

(iv) Four identical crates are placed at A,B,C,DA,B,C,D, with the rest outside the pond covered by grass. Find the smallest grass area to three significant figures. marks

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Square ABCD of side 26 m with central circular pond of radius 11 m and centre P. R is the midpoint of bottom side DC. Q lies on the southeast arc, with angle RPQ=theta between downward PR and PQ. Rectangle QTCS occupies the bottom-right corner: T is on BC, S on DC and C is the square corner. Its area is X square metres. The angle is between zero and pi/4.
Square ABCD of side 26 m with central circular pond of radius 11 m and centre P. R is the midpoint of bottom side DC. Q lies on the southeast arc, with angle RPQ=theta between downward PR and PQ. Rectangle QTCS occupies the bottom-right corner: T is on BC, S on DC and C is the square corner. Its area is X square metres. The angle is between zero and pi/4.
Square ABCD of side 26 m with central circular pond of radius 11 m and centre P. R is the midpoint of bottom side DC. Q lies on the southeast arc, with angle RPQ=theta between downward PR and PQ. Rectangle QTCS occupies the bottom-right corner: T is on BC, S on DC and C is the square corner. Its area is X square metres. The angle is between zero and pi/4.

[2022/SAJC/I/10]

CJC · Review problems · Question 12

Factor the derivative, then compare the boundary with the interior stationary point.

Read the worked solution