Bound the part of C lying in B but outside A

$P(A)=3/5$, $P(B)=3/4$ and $P(A\mid B')=1/2$.

(i) Find $P(A\cap B)$.2 marks

(ii) Find $P(A'\mid A\cup B)$.3 marks

A third event C has $P(C)=1/2$ and is independent of A.

(iii) Find $P(A'\cap C)$.1 mark

(iv) Hence show that $3/40\le P(A'\cap B\cap C)\le1/5$.2 marks