Porisma

Review practice

All chapter practice
  1. 1

    Sketch the curve with equation 16y2−16y−4x2=−316y^2-16y-4x^2=-3, indicating clearly the equation of any asymptote (s) and the coordinates of any stationary point (s). marks

    2012/HCI/Promo/12(a)

  2. 2

    The curve CC has equation y=x2+ax+bc−xy=\dfrac{x^2+ax+b}{c-x}. The vertical asymptote of CC is x=−2x=-2, and the coordinates of the turning points are (−4,2)(-4,2) and (0,−6)(0,-6).

    (i) Find the values of aa, bb and cc. marks

    (ii) Sketch CC, stating the equations of the asymptotes. marks

    (iii) By drawing an appropriate graph on the sketch of CC, find the range of values of kk (k>0)(k>0) such that the equation (x+4)2+(x2+ax+bc−x)2=k2(x+4)^2+\left(\dfrac{x^2+ax+b}{c-x}\right)^2=k^2 has no real roots. marks

    (iv) When CC undergoes a translation in the direction of the yy-axis by pp units, CC intersects the line y=−1y=-1 at one negative value of xx. State the set of values for pp. marks

    2013/PJC/II/5

  3. 3

    The circle with equation x2+(y−k)2=25x^2+(y-k)^2=25, where kk is a real constant, intersects the parabola with equation 4y=x24y=x^2 at four distinct points. Determine the range of values of kk. marks

    2013/RI/JC1/MYE/2

  4. 4

    The curve C1C_1 has equation (x−1)2−y2=1(x-1)^2-y^2=1 and the curve C2C_2 has equation y=1216−x2y=\dfrac12\sqrt{16-x^2}.

    (i) Sketch C1C_1 and C2C_2 on the same diagram, indicating clearly the axial intercepts and the equations of any asymptotes. marks

    (ii) Find the xx-coordinate(s) of the point (s) of intersection of C1C_1 and C2C_2. mark

    (iii) Hence solve the inequality 2(x−1)2−1<16−x22\sqrt{(x-1)^2-1}<\sqrt{16-x^2}. marks

    2014/SRJC/JC1/MYE/4

  5. 5

    The graph of (x−p)2+(y−p)2=p2(x-p)^2+(y-p)^2=p^2, p>0p>0, underwent exactly two simple transformations, involving either reflection, stretching or translation only, to become the ellipse that passes through (0,p)(0,p), (2p,p)(2p,p), (p,3p)(p,3p) and (p,−p)(p,-p).

    (i) Write down the equation of the ellipse. marks

    (ii) Describe clearly (in words) a sequence of the two transformations. mark

    Expand diagram

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    Target ellipse centred at (p, p) for p > 0, through (0, p), (2p, p), (p, 3p), (p, −p). The horizontal semi-axis is p and vertical semi-axis 2p.
    Target ellipse centred at (p, p) for p > 0, through (0, p), (2p, p), (p, 3p), (p, −p). The horizontal semi-axis is p and vertical semi-axis 2p.
    Target ellipse centred at (p, p) for p > 0, through (0, p), (2p, p), (p, 3p), (p, −p). The horizontal semi-axis is p and vertical semi-axis 2p.

    2010/RI/Promo/5(b)

  6. 6

    (a) The curve C1C_1 has equation (x+2)222−y232=1\dfrac{(x+2)^2}{2^2}-\dfrac{y^2}{3^2}=1. Sketch C1C_1, giving the equations of any asymptotes, coordinates of its centre and the vertices. marks

    (b) The curve C2C_2 has equation y=3x2+12x+λ2(x+2)y=\dfrac{3x^2+12x+\lambda}{2(x+2)}, x≠−2x\ne-2, λ∈R\lambda\in\mathbb R, λ≠12\lambda\ne12. Find the range of values of λ\lambda for which the graph of C2C_2 is strictly increasing. marks

    2016/Promo/NYJC/5

  7. 7

    A tunnel is built to facilitate the transportation of goods by trains between Country XX and Country YY. Due to differences in the rail systems between the two countries, two types of tracks are used: the international track with track gauge of 1435 mm and the narrow track with track gauge of 1000 mm (in rail transport, track gauge is the spacing on a railway track). It is known that the cross-section of the tunnel is a half ellipse with centre OO and width MNMN. The maximum height of the tunnel is 2000 mm. To standardize the volumes of the goods to be transported, the areas ABCDABCD and EFGHEFGH are made equal. Find the width of the tunnel MNMN, giving your answer to the nearest mm.

    In the diagram, OO is the midpoint of the base MNMN. AA and BB lie on the base, 1000 mm apart and symmetric about OO, with DD and CC on the tunnel wall directly above them. EE and FF lie on the base, 1435 mm apart and symmetric about OO, with HH and GG on the tunnel wall directly above them.

    Expand diagram

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    Half ellipse of maximum height 2000 mm and base MN, centred at O. Along the base from left to right are M, E, A, O, B, F, N. A and B are 1000 mm apart; E and F are 1435 mm apart. D and C are vertically above A and B; H and G above E and F. Rectangles ABCD and EFGH have equal areas. BC = h₂ and FG = h₁.
    Half ellipse of maximum height 2000 mm and base MN, centred at O. Along the base from left to right are M, E, A, O, B, F, N. A and B are 1000 mm apart; E and F are 1435 mm apart. D and C are vertically above A and B; H and G above E and F. Rectangles ABCD and EFGH have equal areas. BC = h₂ and FG = h₁.
    Half ellipse of maximum height 2000 mm and base MN, centred at O. Along the base from left to right are M, E, A, O, B, F, N. A and B are 1000 mm apart; E and F are 1435 mm apart. D and C are vertically above A and B; H and G above E and F. Rectangles ABCD and EFGH have equal areas. BC = h₂ and FG = h₁.

    2015/HCI/Prelim/I/3