Porisma

Discussion questions · Section 2 of 2

Questions 7–9 in this collection

Use partial fractions before sketching an absolute reciprocal · Recover f from a transformed input graph before reciprocating · +1 more

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  1. 7

    Curve C is f(x)=(x−9)2/[(x−3)(x+3)]f(x)=(x-9)^2/[(x-3)(x+3)].

    (i) Express it as P+Q/(x−3)+R/(x+3)P+Q/(x-3)+R/(x+3).

    (ii) State all asymptotes and axial intercepts.

    (iii) Sketch separately (a) y=f(x)y=f(x) and (b) y=∣1/f(x)∣y=|1/f(x)|, making the main features clear.

    [2007/CJC/I/12]

    CJC · Discussion · Question 7

  2. 8

    The given graph is G(x)=f(3−x/2)G(x)=f(3-x/2), with stationary points (8,−2), (14,2) and x-intercepts 6,10,18. The source diagram shows a vertical asymptote x=0 and left horizontal asymptote y=−4.

    Sketch separately:

    (a) y=1/f(3−x/2)=1/G(x)y=1/f(3-x/2)=1/G(x);

    (b) y=f(x)y=f(x).

    Clearly show asymptotes, stationary points and axial intercepts.

    Expand diagram

    Use the scrollbars or arrow keys to inspect details.

    Source qualitative graph G(x)=f(3-x/2), with pole x=0, min (8,-2), max(14,2), zeros 6,10,18, left horizontal asymptote y=-4 and unbounded decreasing right tail. No exact G formula is supplied; interpolation is schematic.
    Source qualitative graph G(x)=f(3-x/2), with pole x=0, min (8,-2), max(14,2), zeros 6,10,18, left horizontal asymptote y=-4 and unbounded decreasing right tail. No exact G formula is supplied; interpolation is schematic.
    Source qualitative graph G(x)=f(3-x/2), with pole x=0, min (8,-2), max(14,2), zeros 6,10,18, left horizontal asymptote y=-4 and unbounded decreasing right tail. No exact G formula is supplied; interpolation is schematic.

    [2009/AJC/I/11]

    CJC · Discussion · Question 8

  3. 9

    (i) State transformations taking y=x2y=x^2 to y=14(x−3)2y=\frac14(x-3)^2.

    Define

    f(x)={1,0≤x≤1,14(x−3)2,1<x≤3,0,otherwise.f(x)=\begin{cases}1,&0\le x\le1,\\ \frac14(x-3)^2,&1<x\le3,\\0,&\text{otherwise}.\end{cases}

    (ii) Sketch f for −1≤x≤4.

    (iii) Separately sketch y=1+f(x/2)y=1+f(x/2) for −1≤x≤4.

    [2015/I/5]

    CJC · Discussion · Question 9

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