Porisma

When does an inverse exist?

Learn to spot repeated outputs, choose a domain, and keep the correct inverse branch.

By the end, you can

  • Explain why a function is one-to-one
  • Restrict a domain so an inverse exists
  • Find an inverse with its domain and range

about 20 minutes for the lesson · practise at your own pace.

The central idea

A function can be reversed when each output identifies exactly one allowed input. This is the one-to-one condition. For f(x)=x2f(x)=x^2 on all real numbers, f(−2)=f(2)=4f(-2)=f(2)=4. Knowing the output is 4 does not tell us which input was used. A horizontal line crossing the graph twice reveals the same problem.

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Worked example

Keep only x≥0x\geq0. The function is now one-to-one. Write y=x2y=x^2. Since the original input is nonnegative, x=yx=\sqrt{y}. Swap the letters to obtain f−1(x)=xf^{-1}(x)=\sqrt{x} for x≥0x\geq0. The domain of the inverse is the range of the original function: [0,∞)[0,\infty). If we instead kept x≤0x\leq0, the inverse would be −x-\sqrt{x} on the same domain.

Swapping x and y does not fix a function that is many-to-one. Choose a domain first, then keep its sign and endpoint conditions.

Check your understanding

For g(x)=(x−2)2g(x)=(x-2)^2, restricted to x≥2x\geq2, find g−1(x)g^{-1}(x) and its domain. Why must you choose the positive square root?

Practice questions

12 examples and practice questions, in 2 sections.

More practice

Begin with a familiar inverse, then work through more demanding domain restrictions.

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