Integrate twice and solve for the repeated integral
Find . marks
[2023/EJC/Prelim/I/5b]
Solution
Repeated integration by parts
Find .
Hint
Do integration by parts twice, always taking .
The original integral reappears: collect it on the left.
Keep both times; swapping back undoes the first step and goes in a circle.
The printed short key omits , so its expression differentiates to 13 times the integrand. It also contains an unmatched part (a) that is absent from the printed question; the detailed solution supplies the actual requested answer.
Answer · Integral
.
The short key’s missing 1/13 is incorrect.
First round
, , .
Second round
, .
Combine
The original integral has reappeared.
Solve for
Move to the left: . Because this is an indefinite integral, include an arbitrary constant when solving for I.
Divide
Multiply by and rename the arbitrary constant: is still arbitrary.
Explore the idea