14 questions
Solve (2x−18)/(x+3)>x−6(2x-18)/(x+3)>x-6(2x−18)/(x+3)>x−6 algebraically. Hence solve (ln(x2)−18)/(lnx+3)>lnx−6(\ln(x^2)-18)/(\ln x+3)>\ln x-6(ln(x2)−18)/(lnx+3)>lnx−6.
(a) Use graphs to solve x≥2x\sqrt x\ge2xx≥2x. (b) Solve (x−1)(x−3)/(x−2)2<0(x-1)(x-3)/(x-2)^2<0(x−1)(x−3)/(x−2)2<0.
(a) Solve (x2−6)/(2x)>1(x^2-6)/(2x)>1(x2−6)/(2x)>1 exactly. Hence solve (x2−6)/(2∣x∣)≥1(x^2-6)/(2|x|)\ge1(x2−6)/(2∣x∣)≥1. (b) Prove algebraically that x2−4x+9>0x^2-4x+9>0x2−4x+9>0 for all real x. Hence solve (x3+2x2+x+14)/(x2+5)>x+1(x^3+2x^2+x+14)/(x^2+5)>x+1(x3+2x2+x+14)/(x2+5)>x+1.
(a) Without a calculator solve (x+5)/(x−1)>9/x(x+5)/(x-1)>9/x(x+5)/(x−1)>9/x. Hence solve (ex+5)/(ex−1)>9e−x(e^x+5)/(e^x-1)>9e^{-x}(ex+5)/(ex−1)>9e−x. (b) For y=(1+kx)/(x2−1)y=(1+kx)/(x^2-1)y=(1+kx)/(x2−1) with real x≠±1 and −1≤k≤1-1\le k\le1−1≤k≤1, find the range in terms of k.
Solve x∣x−2∣≥1x|x-2|\ge1x∣x−2∣≥1 exactly. Hence solve (x+1)∣x−1∣≥1(x+1)|x-1|\ge1(x+1)∣x−1∣≥1.
Show that tanx+cotx>4\tan x+\cot x>4tanx+cotx>4 for 0<x<π/20<x<\pi/20<x<π/2 simplifies to 0<sin2x<1/20<\sin2x<1/20<sin2x<1/2. Hence solve it exactly in terms of pi.
Show x2−x+1>0x^2-x+1>0x2−x+1>0 for every real x. Hence find all a such that (x2+ax−2)/(x2−x+1)<2(x^2+ax-2)/(x^2-x+1)<2(x2+ax−2)/(x2−x+1)<2 for every real x.
Without a graphing calculator solve x2/(x−1)≤4x≤8x^2/(x-1)\le4x\le8x2/(x−1)≤4x≤8.
Show x2(x+2)2−1=(x+1)2(x+1+2)(x+1−2)x^2(x+2)^2-1=(x+1)^2(x+1+\sqrt2)(x+1-\sqrt2)x2(x+2)2−1=(x+1)2(x+1+2)(x+1−2). Hence solve 1/(x+2)2>x21/(x+2)^2>x^21/(x+2)2>x2 without a calculator. Deduce the inputs satisfying 1/(ex+2)2>e2x1/(e^x+2)^2>e^{2x}1/(ex+2)2>e2x.
Without a graphing calculator solve x≤15/(x+2)x\le15/(x+2)x≤15/(x+2). Hence solve 1/x2≥(x2+2)/151/x^2\ge(x^2+2)/151/x2≥(x2+2)/15.
(i) Without a calculator solve 4/(x+3)≤x4/(x+3)\le x4/(x+3)≤x. (ii) Hence solve 4x/(1+3x)≤1/x4x/(1+3x)\le1/x4x/(1+3x)≤1/x.
(i) Find the exact roots of ∣(4x−5)/(x−2)∣=3x|(4x-5)/(x-2)|=3x∣(4x−5)/(x−2)∣=3x. (ii) Sketch that absolute-value curve and y=3x together. Hence solve ∣(5−4x)/(3x−6)∣>x|(5-4x)/(3x-6)|>x∣(5−4x)/(3x−6)∣>x exactly.
(i) For a<0 and b<−1 solve b∣x−a∣=x−abb|x-a|=x-abb∣x−a∣=x−ab. (ii) Given a<b<0, (a) state the condition on b for a negative real root; (b) under that condition sketch y=x−ab and y=b|x−a| together, solve b∣x−a∣≥x−abb|x-a|\ge x-abb∣x−a∣≥x−ab, and deduce the inputs satisfying −b∣ex+a∣≤ex+ab-b|e^x+a|\le e^x+ab−b∣ex+a∣≤ex+ab.
(i) Sketch y=∣(1/3)2x−18∣y=|(1/3)^{2x}-18|y=∣(1/3)2x−18∣, finding exact intercepts. (ii) Without a calculator, solve ∣(1/3)2x−18∣≤9|(1/3)^{2x}-18|\le9∣(1/3)2x−18∣≤9 with full working, giving the exact interval or intervals in their simplest form.