23 questions
The position vectors of A, B and C relative to origin O are −i+5j+k-\mathbf i+5\mathbf j+\mathbf k−i+5j+k, i−j+5k\mathbf i-\mathbf j+5\mathbf ki−j+5k and pi−4j+7kp\mathbf i-4\mathbf j+7\mathbf kpi−4j+7k respectively, where ppp is constant. Given A, B and C are collinear, show p=2p=2p=2. ****
Relative to origin O, P and Q have position vectors p,q\mathbf p,\mathbf qp,q, nonparallel and nonzero. R lies on PQ produced with PQ:QR=1:λPQ:QR=1:\lambdaPQ:QR=1:λ. M is the midpoint of OR.
Lines l1,l2l_1,l_2l1,l2 are r=(1,0,1)+λ(1,1,−2)\mathbf r=(1,0,1)+\lambda(1,1,-2)r=(1,0,1)+λ(1,1,−2) and r=(1,2,−1)+μ(7,5,1)\mathbf r=(1,2,-1)+\mu(7,5,1)r=(1,2,−1)+μ(7,5,1) respectively.
Relative to origin O, A and B have position vectors a=3i+j+3k\mathbf a=3\mathbf i+\mathbf j+3\mathbf ka=3i+j+3k and b=5i−4j+3k\mathbf b=5\mathbf i-4\mathbf j+3\mathbf kb=5i−4j+3k.
A and B have position vectors a,b\mathbf a,\mathbf ba,b relative to O, with ∣a∣=∣b∣|\mathbf a|=|\mathbf b|∣a∣=∣b∣. P with position vector p\mathbf pp lies on AB such that b⋅p=a⋅p\mathbf b\cdot\mathbf p=\mathbf a\cdot\mathbf pb⋅p=a⋅p.
Relative to O, A and B have position vectors a,b, nonzero and nonparallel.
(i) State the shortest distance from B to the line through O,A. ****
Line l passes through A(1,2,−1)(1,2,-1)(1,2,−1) and B(2,a,1)(2,a,1)(2,a,1). Given l cuts the x-axis, show a=−2a=-2a=−2. **** Find the shortest distance of O from l. ****
A,B,C have position vectors a,b,c relative to O. AC→=4CB→\overrightarrow{AC}=4\overrightarrow{CB}AC=4CB and ∣a+b∣2=∣a∣2+∣b∣2|\mathbf a+\mathbf b|^2=|\mathbf a|^2+|\mathbf b|^2∣a+b∣2=∣a∣2+∣b∣2.
Relative to O, A,B,D have position vectors a,b,d. OACB is a parallelogram and ∠OAC=2π/3\angle OAC=2\pi/3∠OAC=2π/3 radians.
Planes Π1,Π2\Pi_1,\Pi_2Π1,Π2 are r⋅(2,4,1)=10\mathbf r\cdot(2,4,1)=10r⋅(2,4,1)=10 and r⋅(1,3,1)=8\mathbf r\cdot(1,3,1)=8r⋅(1,3,1)=8.
Line l passes through A(−1,2,3)(-1,2,3)(−1,2,3) and B(5,14,11)(5,14,11)(5,14,11). Plane p is 2x+3y−6z=−72x+3y-6z=-72x+3y−6z=−7.
Plane π1\pi_1π1 and line l are r⋅(2,1,−2)=6\mathbf r\cdot(2,1,-2)=6r⋅(2,1,−2)=6 and (x−1)/3=(y+4)/2=z−5(x-1)/3=(y+4)/2=z-5(x−1)/3=(y+4)/2=z−5 respectively. A has position vector 3i−j+4k3\mathbf i-\mathbf j+4\mathbf k3i−j+4k.
A plane π1\pi_1π1 has equation r⋅(2,−1,3)=9\mathbf r\cdot(2,-1,3)=9r⋅(2,−1,3)=9 and a line l1l_1l1 has equation r=(3,0,0)+λ(4,1,−2)\mathbf r=(3,0,0)+\lambda(4,1,-2)r=(3,0,0)+λ(4,1,−2).
The diagram above shows a cuboid with horizontal rectangular base ABCDABCDABCD, where AB=5AB=5AB=5 units, AD=3AD=3AD=3 units and AP=2AP=2AP=2 units. The edges AP,BQ,CR,DSAP,BQ,CR,DSAP,BQ,CR,DS are vertical, and PQRSPQRSPQRS is the top of the cuboid. The point AAA is taken as the origin and vectors i,j,k\mathbf i,\mathbf j,\mathbf ki,j,k, each of length 1 unit, are taken along AB,AD,APAB,AD,APAB,AD,AP respectively.
The plane p1p_1p1 has equation x+y−2z=4x+y-2z=4x+y−2z=4. A plane p2p_2p2 with equation 2x+ay+bz=−42x+ay+bz=-42x+ay+bz=−4 (where a,ba,ba,b are constants) is parallel to p1p_1p1, find the values of a,ba,ba,b and also the exact distance between p1,p2p_1,p_2p1,p2.
Relative to the origin OOO, the point AAA has position vector OA→=(0,1,0)\overrightarrow{OA}=(0,1,0)OA=(0,1,0) and AAA lies on the plane Π1\Pi_1Π1 with equation defined by r⋅(1,3,2)=3\mathbf r\cdot(1,3,2)=3r⋅(1,3,2)=3. Another plane Π2\Pi_2Π2 has equation y=xy=xy=x. The planes Π1,Π2\Pi_1,\Pi_2Π1,Π2 intersect at line lll.
The equations of the line l1l_1l1 and the plane p1p_1p1 are respectively, r=(1,0,0)+μ(−1,1,1)\mathbf r=(1,0,0)+\mu(-1,1,1)r=(1,0,0)+μ(−1,1,1) and r=s(1,1,1)+t(2,−1,1)\mathbf r=s(1,1,1)+t(2,-1,1)r=s(1,1,1)+t(2,−1,1), where μ,s,t∈R\mu,s,t\in\mathbb Rμ,s,t∈R.
The points A,BA,BA,B have position vectors 3i+j3\mathbf i+\mathbf j3i+j and 3i+3j3\mathbf i+3\mathbf j3i+3j respectively. The line l1l_1l1 and the planes Π1,Π2\Pi_1,\Pi_2Π1,Π2 have equations as follows:
A home interior designer is looking to design a pull-down wardrobe lift. To test his concept, the designer built a small-scale model of it, in which points (x,y,z)(x,y,z)(x,y,z) are defined relative to a corner of the model at O(0,0,0)O(0,0,0)O(0,0,0). The rods used in the model can be modelled by equations of straight lines.
Laser (Light Amplification by Stimulated Emission of Radiation) has many applications including medicine, data storage, military and industrial uses. It has the property of spatial coherence, which allows the laser beam to stay narrow over long distances. When a laser beam is projected onto a mirror at an angle, it reflects off the mirror at the same angle.
Peter is using equations of planes to model two hillsides that meet along a river. The river is modelled by the line where the two planes meet.
Figure 1 shows a methane molecule consisting of a carbon atom with four hydrogen atoms symmetrically placed around it. Figure 2 shows the tetrahedron structure of the methane molecule with the centres of the hydrogen atoms represented by points Q,R,S,TQ,R,S,TQ,R,S,T and the centre of the carbon atom represented by point VVV.
The diagram above shows a partial design of the roof of the gallery of an amphitheatre. ABCDABCDABCD is an inclined rectangular roof, where AB=10AB=10AB=10 m and BC=5BC=5BC=5 m. EFGHEFGHEFGH is a rectangle on a horizontal ground, where EF=10EF=10EF=10 m and EH=4EH=4EH=4 m. The points A,BA,BA,B are 3 m directly above E,FE,FE,F respectively. The points C,DC,DC,D are 6 m directly above G,HG,HG,H respectively.