Use as the coordinate that only goes one way
C: , , where is real. A line l cuts C at two points P and Q with parameters and , respectively, as shown. Find the area bounded by C and l to 3 significant figures. marks
[2011/TPJC/Prelim/I/1]
Solution
Parametric area
The curve has parametric equations , , where is real. A line cuts at the points and with parameters and respectively. Find the area bounded by and , correct to 3 significant figures.
Hint
Find the coordinates of and .
Is steadily increasing along the arc from to ? If so, use horizontal strips and integrate .
The region is a trapezium (between and the -axis) with the part between and the -axis removed.
The curve turns back in : vertical strips require splitting the branches and tracking their limits. Horizontal strips give one curve value at each height and avoid that split.
After writing , change the limits to : and .
The line is to the right of the curve at every height in , so the area is (line − curve), not the reverse.
Answer · A
square units (3 s.f.).
Source-selected arc −1/2≤t≤1. Full real-parameter curve also meets the line at t=7, giving a different additional region.
Coordinates of and
gives and . gives and .
Specify the requested region
Substitute , into the line through P and Q. Besides the named intersections , there is a third at . The source’s two-point description is incomplete; the pictured P–Q region uses only .
Why horizontal strips work
increases strictly with , so each height between and meets the curve exactly once. Vertical strips would be awkward, because visits the same twice.
Trapezium minus the area inside the curve
Seen sideways, the region between and the -axis is a trapezium with parallel sides and and height . Subtracting the area between and the -axis leaves the area we want. The trapezium is .
Convert to
, and the limits correspond to .
Evaluate
At the bracket is . The integral is and the trapezium is , so the area is , which is to 3 s.f.
Explore the idea
Pick the variable that does not turn back
Before integrating a parametric curve, check which of and is monotonic along the arc. Integrating with respect to that one means the curve is a function, and the area formula or applies directly.