Porisma

A hint to get started

Sketch an exact rational function and two different modulus graphs

Given F(x)=(2x−x2)/(x2−2x−3)F(x)=(2x-x^2)/(x^2-2x-3), find:

(i) the asymptotes;

(ii) where the curve cuts the axes;

(iii) the stationary point.

Hence sketch F and use it to obtain separate graphs of y=∣F(x)∣y=|F(x)| and y=(2∣x∣−x2)/(x2−2∣x∣−3)=F(∣x∣)y=(2|x|-x^2)/(x^2-2|x|-3)=F(|x|).

CJC · Discussion · Question 5

An absolute value outside the function changes ordinates; inside it changes which input branch is used.

Read the worked solution