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Differential equations

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Apply initial data and an inverse-square gradient law

(a) Solve cos⁡2x dy/dx=1\cos^2x\,dy/dx=1 for 0<x<π/20<x<\pi/2, given y=0y=0 when x=π/4x=\pi/4, expressing y as a function of x.

(b) Find the equation of a curve through (1,2)(1,2) and (1/4,−10)(1/4,-10) whose gradient is inversely proportional to x2x^2.

CJC · Lecture · Self-Practice 1

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