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Question 13 in this collection

Combine a leaking cone with trapezium optimisation

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  1. 13

    (a) A factory produces disposable cups in the shape of inverted right cones of radius 44 cm and height 88 cm. For a quality check, the supervisor fills one cup completely with water. Water leaks from its vertex at a constant 1.5 cm3 s−11.5\text{ cm}^3\text{ s}^{-1}. Find the exact rate at which the water level is decreasing when its depth is 22 cm. marks

    The volume of a cone of base radius rr and height hh is 13πr2h\tfrac13\pi r^2h.

    (b) Trapezium ABCDABCD has height 55 cm and DA+AB+BC=20DA+AB+BC=20 cm. Points M,NM,N are the feet of the perpendiculars from A,BA,B to DCDC. Given ∠DAM=∠CBN=θ\angle DAM=\angle CBN=\theta, where 0<θ<π/20<\theta<\pi/2:

    (i) Show that its area is A=100−50sec⁡θ+25tan⁡θ cm2A=100-50\sec\theta+25\tan\theta\text{ cm}^2. marks

    (ii) Hence use differentiation to find its maximum area in exact form. You do not need to verify that it is a maximum. marks

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    Two given diagrams. (a) An inverted conical cup with top radius 4 cm and vertical height 8 cm, with a smaller water cone inside and leakage at its bottom vertex. (b) Trapezium ABCD with top AB, longer base DC and perpendiculars AM and BN of length 5 cm. The equal angles theta lie between AD and AM at A, and between BC and BN at B. The sum DA+AB+BC is 20 cm.
    Two given diagrams. (a) An inverted conical cup with top radius 4 cm and vertical height 8 cm, with a smaller water cone inside and leakage at its bottom vertex. (b) Trapezium ABCD with top AB, longer base DC and perpendiculars AM and BN of length 5 cm. The equal angles theta lie between AD and AM at A, and between BC and BN at B. The sum DA+AB+BC is 20 cm.
    Two given diagrams. (a) An inverted conical cup with top radius 4 cm and vertical height 8 cm, with a smaller water cone inside and leakage at its bottom vertex. (b) Trapezium ABCD with top AB, longer base DC and perpendiculars AM and BN of length 5 cm. The equal angles theta lie between AD and AM at A, and between BC and BN at B. The sum DA+AB+BC is 20 cm.

    [2022/TMJC/I/6]

    CJC · Discussion · Question 13

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