Porisma

Discussion questions

All chapter practice
  1. 1

    Sketch each graph, clearly indicating asymptotes, axial intercepts and coordinates of any turning points.

    (a) y=2x3−5x2+x−2y=2x^3-5x^2+x-2.

    (b) y=4x2exy=4x^2e^x.

    (c) y=ln⁡x/(2x)y=\ln x/(2x).

    (d) y=(x2+2x−8)/(x2+2x−3)y=(x^2+2x-8)/(x^2+2x-3).

    (e) y=∣2x−x2∣y=|2x-x^2|.

    (f) y=(ax+1)/(x−b)y=(ax+1)/(x-b), where (i)−1<a<0,0<b<1; or (ii)a<−1,b>1. What happens if ab+1=0?

    CJC · Discussion · Question 1

  2. 2

    C has equation y=x2/(x−2)y=x^2/(x-2).

    (i) Find the asymptotes. mark

    (ii) Sketch C, labelling asymptotes, axial intercepts and turning points. marks

    (iii) Hence find the values of k for which x2=k(x2−4)x^2=k(x^2-4) has no real roots. marks

    [2013/YJC/I/12]

    CJC · Discussion · Question 2

  3. 3

    C has equation y=(x2+9x+16)/(x+2)y=(x^2+9x+16)/(x+2).

    (i) Find its asymptotes.

    (ii) Find, in exact form, all k for which k=(x2+9x+16)/(x+2)k=(x^2+9x+16)/(x+2) has no real roots.

    (iii) Sketch C with asymptotes, stationary points and x-/y-axis intersections labelled.

    [2009/IJC/II/1]

    CJC · Discussion · Question 3

  4. 4

    C1C_1 has equation y=(ax2+bx)/(x+c)y=(ax^2+bx)/(x+c).

    (i) It has vertical asymptote x=2 and an oblique asymptote through (0,10) and (−2,0). Find a,b,c.

    (ii) Hence sketch C1C_1, clearly stating all asymptotes and stationary points.

    [2014/NJC/MYE/7(part)]

    CJC · Discussion · Question 4

  5. 5

    C has equation y=(x2+ax+4)/(x+b)y=(x^2+ax+4)/(x+b), with vertical asymptote x=−1 and a stationary point at x=2.

    (i) Find a and b.

    (ii) Find the other asymptote.

    (iii) Without a calculator, find the set of values y cannot take.

    (iv) Sketch C, showing axial intercepts, asymptotes and stationary points.

    (v) Deduce the number of real roots of (4−x2)(x+1)2=(x2−4x+4)2(4-x^2)(x+1)^2=(x^2-4x+4)^2.

    [2007/HCI/I/13(modified)]

    CJC · Discussion · Question 5

  6. 6

    · Techniques of Differentiation

    C has equation y=(2x2+ax+3a)/(x+b)y=(2x^2+ax+3a)/(x+b), where a,b are nonzero constants. x=2 is an asymptote.

    (i) State b.

    (ii) By differentiation, find the range of a for which C has no stationary points.

    (iii) Given a=−3, sketch C with all asymptotes and axis intersections.

    [2009/RJC/I/10]

    CJC · Discussion · Question 6