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Sequences and series

Practice section 7 of 17

Questions 37–42 in this collection

Practice questions

Worked example · 1 of 6

Total the doubling reward on a chessboard

In the source legend, a chess inventor asks for one grain of rice on the first square, two on the second, four on the third, eight on the fourth, and twice as many on each following square. How many grains are required in total for all 6464 squares?

CJC · Sequences and Series · Unnumbered rice-grain and chessboard question

Solution

Worked example · 5 of 6

Take the limit of a given partial sum

Given that ∑n=1N1n(n+1)(n+2)=14−12(N+1)+12(N+2)\displaystyle\sum_{n=1}^{N}\frac1{n(n+1)(n+2)}=\frac14-\frac1{2(N+1)}+\frac1{2(N+2)}, explain whether the series is convergent or divergent, and state the sum to infinity if it is convergent.

CJC · Sequences and Series · Example 26

Solution

Worked example · 6 of 6

Classify infinite series from their partial sums

Classify the series represented by these partial sums as convergent or divergent, giving the finite limit when one exists. (a) ∑j=1n2j=2(2n−1)\sum_{j=1}^{n}2^j=2(2^n-1). (b) Given ∑j=1n1j(j+2)=34−12(n+1)−12(n+2)\sum_{j=1}^{n}\frac1{j(j+2)}=\frac34-\frac1{2(n+1)}-\frac1{2(n+2)}. (c) An AP with Sn=n2[2a+(n−1)d]S_n=\frac n2[2a+(n-1)d], for d>0d>0 and d<0d<0. (d) A GP with Sn=a(rn−1)r−1S_n=\frac{a(r^n-1)}{r-1}, r>1r>1, a≠0a\ne0. (e) A GP with Sn=a(1−rn)1−rS_n=\frac{a(1-r^n)}{1-r}, ∣r∣<1|r|<1.

CJC · Sequences and Series · Convergence comparison table

Solution

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